Can high voltage LEDs reduce the area of ​​the LEDs? indeed so. For example, for a 36W LED, if you use 36 1W LEDs, it will occupy a large area, and if you do an integrated 36W high voltage LED, then only a small area.
This seems to be an advantage, but it is not necessarily an advantage from the point of view of heat dissipation. Because if the luminous efficiencies of the two are the same, then the heat they will emit is the same. In a small area, a lot of heat is emitted, which will be a big problem in the design of the heat sink. In fact, manufacturers of integrated LEDs have noticed this problem and have made many improvements.
The first is to reduce its thermal resistance. The thermal resistance of a typical 1W LED is about 6-9 ° C / W, and the thermal resistance of the integrated LED can be reduced to 2 ° C / W or even smaller. Secondly, its backing plate is changed to copper to improve its heat conduction. However, these measures cannot fundamentally improve the basic situation of small areas of high heat.
The only way to get the heat out quickly is to use a heat pipe. This will increase the cost of the radiator. Similarly, since the bottom plate of the high-voltage LED is made of copper, the part of the heat sink that is in direct contact with it must also be made of copper instead of aluminum, because the expansion coefficients of the two are different, and direct contact causes a gap and affects heat conduction. If you use a copper radiator, it will increase the cost.
Therefore, this high-voltage LED will not only reduce the cost of the heat sink, but will increase the cost of the heat sink.
This seems to be an advantage, but it is not necessarily an advantage from the point of view of heat dissipation. Because if the luminous efficiencies of the two are the same, then the heat they will emit is the same. In a small area, a lot of heat is emitted, which will be a big problem in the design of the heat sink. In fact, manufacturers of integrated LEDs have noticed this problem and have made many improvements.
The first is to reduce its thermal resistance. The thermal resistance of a typical 1W LED is about 6-9 ° C / W, and the thermal resistance of the integrated LED can be reduced to 2 ° C / W or even smaller. Secondly, its backing plate is changed to copper to improve its heat conduction. However, these measures cannot fundamentally improve the basic situation of small areas of high heat.
The only way to get the heat out quickly is to use a heat pipe. This will increase the cost of the radiator. Similarly, since the bottom plate of the high-voltage LED is made of copper, the part of the heat sink that is in direct contact with it must also be made of copper instead of aluminum, because the expansion coefficients of the two are different, and direct contact causes a gap and affects heat conduction. If you use a copper radiator, it will increase the cost.
Therefore, this high-voltage LED will not only reduce the cost of the heat sink, but will increase the cost of the heat sink.
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